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Q.
The value of a third order determinant is 5, then this value of the square of the determinant formed by its co-factors will be:
Determinants
Solution:
Note: Value of a determinant is the sum of the products of the elements of any row or column with the corresponding cofactor.
Given value of determinant = 5
Order of determinant = 3 $\times$ 3
Thus, let A be the value of determinant and n be the order. Then the square of the
determinant formed by its cofactors
$= | A |^n = 5^3 = 125$