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  4. The value of 9950-99.9850+(99.98/1.2)(97)50 ldots ldots+99 is

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Q. The value of $99^{50}-99.98^{50}+\frac{99.98}{1.2}(97)^{50} \ldots \ldots+99$ is

Binomial Theorem

Solution:

Correct answer is '0'