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Q. The value of $(9.6)^2=$___

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Solution:

$(9.6)^2=(10.0-0.4)^2$
$\text { Since, } (a-b)^2 =\left(a^2-2 a b+b^2\right) $
$ =(10)^2-2 \times 10 \times(0.4)+(0.4)^2$
$ =100-8+0.16=92.16$