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Q. The value of $9^{1 / 3} \cdot 9^{1 / 9} \cdot 9^{1 / 27} \ldots \ldots$ upto $\infty$, is-

Sequences and Series

Solution:

We have to find value of $9^{1 / 3} \cdot 9^{1 / 9} \cdot 9^{1 / 27}$ $\infty=x$ (say)
We can see that powers are in G.P. and $|r|<1$
$\therefore x=9^{\frac{\frac{1}{3}}{1-\frac{1}{3}}}=9^{12}=3$