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Q. The value of $(10.4)^2$ is___

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Solution:

$ (10.4)^2=(10+0.4)^2 $
$=(10)^2+2 \times 10 \times 0.4+(0.4)^2 $
$ \text { Since }(a+b)^2=(a)^2+2 a b+b^2 $
$ =100+8+0.16=108.16 $