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Q. The $V-T$ graph shows some process for an ideal gas. The $INCORRECT$ statement is:
Question

NTA AbhyasNTA Abhyas 2022

Solution:

For $A \rightarrow B:v \propto T$
$P$ is constant
For $C \rightarrow D:v=mT+C$
$\frac{nRT}{P}=mT+C$
$P=\frac{nRT}{mT + C}=\frac{nR}{\left(m + \frac{C}{T}\right)}$
$P$ increases, as $T$ increases.
For $E \rightarrow F:P=\frac{nRT}{mT - C}=\frac{nRT}{m - \frac{C}{T}}$
$P$ decreases, as $T$ increases.