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Q. The $V$ - $i$ graph for a good conductor makes angle $40^{\circ}$ with $V$-axis. Here, $V$ denotes voltage and $i$ denotes current. The resistance of the conductor will be

Current Electricity

Solution:

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According to Ohm's law, we get
Current $I=\frac{V}{R}$. So, slope $A B$
i.e., $\tan 40^{\circ}=\frac{I}{V} $
$\Rightarrow \frac{1}{\tan 40^{\circ}}=\frac{V}{I} $
$\Rightarrow \cot 40^{\circ}=\frac{V}{I}$
$\left(\because\right.$ slope of $A B$ i.e., $\left.R=\frac{V}{I}\right)$