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Q.
The unit of Stefan's constant is
MGIMS WardhaMGIMS Wardha 2008
Solution:
According to Stefan's law, the energy radiated per second or power radiated is given by $ P=\sigma A{{T}^{4}} $ $ \therefore $ $ \sigma =\frac{P}{A{{T}^{4}}} $ Therefore, unit of $ \sigma =\frac{W}{{{m}^{2}}{{K}^{4}}}=W{{m}^{-2}}{{K}^{-4}} $