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  4. The unit of specific conductivity is

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Q. The unit of specific conductivity is

Electrochemistry

Solution:

Specific conductivity
$K = \frac{1}{R} \times\frac{l}{a} = \frac{1}{ohm} \times\frac{cm}{cm^{2}}$
$= ohm^{-1}\, cm^{-1}$