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Q. The unit of ebullioscopic constant is ______.

JIPMERJIPMER 2015Solutions

Solution:

As we know from elevation in boiling point that $U$

$\Delta T_b = K_b m$

Unit of $K_b = \frac{\text{Unit of } \Delta T_b}{\text{Unit of} \,m}$

$= \frac{K}{mol\,kg^{-1}} = K\,mol^{-1} kg$