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Q. The unit, $mol \, L^{-1} \, s^{-1}$ is meant for the rate constant of the reaction having the order

KEAMKEAM 2009Chemical Kinetics

Solution:

General unit for rate constant = $\big(\frac{mol}{L}\big)^{1-n} \, s^{-1}$
(where, n = order of reaction)
Given, unit for rate constant = $\big(\frac{mol}{L}\big) \, s^{-1}$
On comparing,
$ \big(\frac{mol}{L}\big)^{1-n} \, s^{-1} = \big(\frac{mol}{L}\big) \, s^{-1}$
$ 1 - n = 1$
$\therefore n = 0$
Hence, the order of reaction is zero.