Question

The unit $J \,Pa ^{-1}$ is equivalent to

• A. $m ^{3}$
• B. $cm ^{3}$
• C. $dm ^{3}$
• D. None of these

Answer 1

Answer: (A)

$JPa ^{-1} ;$ Unit of work is Joule and unit of pressure is Pascal.

Dimension of Joule i.e. work $= F \times L = MLT ^{-2} \times L$

$=\left[ ML ^{2} T ^{-2}\right]$

$\frac{1}{P a}=\frac{1}{\text { Pressure }}=\frac{1}{\frac{F}{A}}=\frac{1 \times A}{F}=\left[M L T^{-1}\right]$

So, $\left. JPa ^{-1}=\left[ ML ^{2} T ^{-2}\right]=\left[ L ^{2} \times L \right]=\right]\left[ L ^{3}\right] .$