Question

The unit cell of copper corresponds to a face centered cube of edge length $3.596\mathring{A} $ with one copper atom at each lattice point. The calculated density of copper in $kg/m^{3}$ is _________. [Molar mass of $Cu=63.54g$ ; Avogadro's number $=6.022\times 10^{23}$ ] (Round off answer to nearest integer value).

Answer 1

Given:
$a=3.596\mathring{A} $
$d=\frac{Z \times M}{N_{A} \times a^{3}}$
$d=\frac{4 \times 63 . 54 \times \left(10\right)^{- 3}}{6 . 022 \times \left(10\right)^{23} \times \left(3 . 596 \times \left(10\right)^{- 10}\right)^{3}}$
$d=0.9076\times 10^{4}=9076kg/m^{3}$