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  4. The unbalanced equation for the reaction of P4S3 with nitrate in aqueous acidic medium is given below. P4S3+NO3- arrow H3PO4+SO42 -+NO The number of moles of water required per mol of P4S3 is (x/3) , the value of textx is

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Q. The unbalanced equation for the reaction of $P_{4}S_{3}$ with nitrate in aqueous acidic medium is given below.
$P_{4}S_{3}+NO_{3}^{-} \rightarrow H_{3}PO_{4}+SO_{4}^{2 -}+NO$
The number of moles of water required per mol of $P_{4}S_{3}$ is $\frac{x}{3}$ , the value of $\text{x}$ is

NTA AbhyasNTA Abhyas 2022

Solution:

$P _{4} S _{3}+ NO _{3}^{-} \rightarrow H _{3} PO _{4}+ SO _{4}^{2-}+ NO$
$\left( P _{4} S _{3}+28 H _{2} O \rightarrow 4 H _{3} PO _{4}+3 SO _{4}^{2-}+44 H ^{+}+38 e ^{-}\right) \times 3$
$\left( NO _{3}^{-}+4 H ^{+}+3 e ^{-} \rightarrow NO +2 H _{2} O \right) \times 38$
$\therefore 3 P _{4} S _{3}+38 NO _{3}^{-}+8 H _{2} O +20 H ^{+} \rightarrow 12 H _{3} PO _{4}+9 SO _{4}^{2-}+38 NO$