Question

The type of hybridisation of $P$ atom in $PCl _{5},\, PCl _{ 4 }^{+}$ and $PCl _{ 6 }^{-}$ is (respectively)

• A. $s p^{3}, sp^{2} d s p^{3} d^{2}$
• B. $s p^{3} d, s p^{3}, s p^{2} d^{2}$
• C. $s p^{3} s p^{3} d^{2}, s p^{3}$
• D. $s p^{3} d^{2}, s p^{3}, s p^{3} d$

Answer 1

Answer: (B)

In $P C l_{5}$ No. $e^{-}$ pairs around central atom $P=5$
No of lone pairs $=0$ and hybridisation- $s p^{3} d$ Shape $=$ trigonal bipyramidal.
In $P C l_{4}^{+}-$ number, of $e^{-}$ pairs $=4$, lone pairs $=0$, hybridisation $=s p^{3}$ and shape $-$ tetrahedral
In $P C l_{6}^{-}-$ number of $e^{-}$ pairs $=6$, lone pairs $=0$, hybridisation $=s p^{3} d^{2}$ and shape is octahedral