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Q. The type of hybrid orbitals used by iodine atom in hypoiodous acid molecule are

AIIMSAIIMS 2010

Solution:

Word 'hypo' reveals that in it I is in $+1$ oxidation state, ie, it is iodous (I) acid or HOI. In HOI,
number of hybrid orbitals
$=\frac{1}{2}[7+1-0+0]=4$
$\therefore $ In it, iodine atom uses $s p^{3}$ hybrid orbitals.