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Q. The two ions $A ^{+}$and $B ^{-}$have radii $88$ and $200\, pm$ respectively. In the closed packed crystal of compound $A B$, Predict the co-ordination number of $A^{+}$.

The Solid State

Solution:

$\frac{r_{+}}{r_{-}}=0.44$
Since, $0.414<\frac{r_{+}}{r_{-}}<0.732$
$A^{+}$occupies octahedral void
$\Rightarrow C No. =6$