Q.
The truth table for the given logic circuit is
TS EAMCET 2019
Solution:
The given logic circuit can be redrawn as,
So, from the above expression (boolean expression)of Y the truth table is shown below,
A
B
$\bar{A}$
$\bar{B}$
$A.\bar{B}$
$\bar{A}.B$
$Y$
0
0
1
1
0
0
0
0
1
1
0
0
1
1
1
0
0
1
1
0
1
1
1
0
0
0
0
0
| A | B | $\bar{A}$ | $\bar{B}$ | $A.\bar{B}$ | $\bar{A}.B$ | $Y$ |
| 0 | 0 | 1 | 1 | 0 | 0 | 0 |
| 0 | 1 | 1 | 0 | 0 | 1 | 1 |
| 1 | 0 | 0 | 1 | 1 | 0 | 1 |
| 1 | 1 | 0 | 0 | 0 | 0 | 0 |