Q.
The true statement for the acids of phosphorus, $H_3PO_2$,
$H_3PO_3$ and $H_3PO_4$ is
Solution:
$H_3PO_2, H_3PO_3$ and $H_3PO_4$ contain one, two and three ionisable hydrogen atoms respectively.
$H_3PO_2 \rightleftharpoons H^+ + H_2PO_2^-$
$H_3PO_3 \rightleftharpoons H+ + H_2PO_3^- \rightleftharpoons H^+ + HPO_3^{2-}$
$H_3PO_4 \rightleftharpoons H^+ + H_2PO_4^- \rightleftharpoons H^+ + HPO_4^{2-}$
$\rightleftharpoons H^+ + PO_4^{3-}$
But there is very little difference in acidity.
As P is $sp^3$ hybridised in all therefore all are tetrahedral.
