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Q. The triple point of carbon dioxide is $216.55\, K$ the corresponding temperature on the Celsius and Fahrenheit scale respectively are

Thermal Properties of Matter

Solution:

As $T_{C}=\left(T-273\right)^{\circ}C$
$=216.55-273=-56.45^{\circ}C$
Also, $T_{F}=\frac{9}{5}T_{C}+32$
$=\frac{9}{5} \times\left(-56.45\right)+32$
$=-101.61+32=-69.61^{\circ}F$