Question

The transfer characteristic curve of a transistor, having input and output resistance $100 \, \Omega $ and $100 \, k\Omega $ respectively, is shown in the figure. The voltage and power gain, are respectively:

• A. $5\times 10^{4}, \, 2.5\times 10^{6}$
• B. $2.5\times 10^{4}, \, 2.5\times 10^{6}$
• C. $5\times 10^{4}, \, 5\times 10^{6}$
• D. $5\times 10^{4}, \, 5\times 10^{5}$

Answer 1

Answer: (A)

Current gain $\left(\beta \right)=\frac{\Delta I_{C}}{\Delta I_{B}}= \, \frac{5 \, \times \left(10\right)^{- 3 \, }}{100 \, \times \left(10\right)^{- 6}}=50$
Voltage gain $\left(\mathrm{A}_{\mathrm{V}}\right)=\beta\left(\frac{R_{\text {out }}}{R_{\text {in }}}\right)=50 \times \frac{100 \times 10^3}{100}=5 \times 10^4$
Power gain $=A_{V}\times \beta =50\times 5\times 10^{4}=2.5\times 10^{6}$