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  4. The total resistance in the parallel combination of three resistances 9 Ω, 7 Ω and 5 Ω is

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Q. The total resistance in the parallel combination of three resistances $9\,\Omega$, $7\,\Omega$ and $5\,\Omega$ is

Current Electricity

Solution:

In the parallel combination of three resistances, the equivalent resistance is
$\frac{1}{R_{eq}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}$
or $\frac{1}{R_{eq}}=\frac{1}{9}+\frac{1}{7}+\frac{1}{5}=\frac{143}{315}$ ;
$R_{eq}=\frac{315}{143}=2.20\,\Omega$