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Q.
The total positive charge in a glass of water containing 180 gm of water is approximately :
Electric Charges and Fields
Solution:
The number of molecules in 18 g of water $= 6.02 \times 10^{23}$
$\therefore $ Number of molecules in 180 g of water
$ = 6.02 \times 10^{23} \times \frac{180}{18} = 6.02 \times 10^{24}$
The number of protons in a molecule of water = 10
So, total number of protons,
$n = 6.02 \times 10^{24} \times 10 = 6.02 \times 10^{25}$
The total charge, q = ne
$= 6.02 \times 10^{25} \times 1.6 \times 10^{-19} = 0.96 \times 10^7$
$\approx \, 1.0 \times 10^7 \, C$.