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  4. The total number of valence electrons in 4.2 g of N 3-ion is [NA. is the Avogadro's number]

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Q. The total number of valence electrons in $4.2\, g$ of $N _{3}^{-}$ion is $\left[N_{A}\right.$ is the Avogadro's number]

AIPMTAIPMT 1994Some Basic Concepts of Chemistry

Solution:

Moles of $N_{3}^{-}$ion $=\frac{4.2}{42}=0.1$
Each nitrogen atom has 5 valence electrons.
Therefore, total number of electrons in $N_{3}^{-}$ion $=16$
Total number of electrons in $0.1$ mole or
$4.2 g $ of $ N_{3}^{-} $ ion $=0.1 \times 16 \times N_{A} $
$=1.6 N_{A}$