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Q. The total number of protons present in $124g$ of $NO_{3}^{-}$ are:

NTA AbhyasNTA Abhyas 2022

Solution:

Protons in $NO_{3}^{-}=31$
$Moles$ of $NO_{3}^{-}=\frac{124}{62}=2mole$
$1moleNO_{3}^{-}=31N_{A}$ protons
$2moleNO_{3}^{-}=62N_{A}$