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  4. The total number of possible isomers of the complex compound |CuII(NH3)4||PtIICl4| is

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Q. The total number of possible isomers of the complex compound $ |C{{u}^{II}}{{(N{{H}_{3}})}_{4}}||P{{t}^{II}}C{{l}_{4}}| $ is

MGIMS WardhaMGIMS Wardha 2015

Solution:

$ |C{{u}^{II}}(N{{H}_{3}})||P{{t}^{II}}C{{l}_{4}}| $ shows $ |Cu(N{{H}_{3}})Cl||PtC{{l}_{3}}N{{H}_{3}}|, $ $ |Cu(N{{H}_{3}})C{{l}_{3}}||Pt{{(NH)}_{3}}Cl| $ and $ |CuC{{l}_{4}}||Pt{{(N{{H}_{3}})}_{4}}| $ .Other isomers such as $ |Cu{{(N{{H}_{3}})}_{2}}C{{l}_{2}}||Pt{{(N{{H}_{3}})}_{2}}C{{l}_{2}}| $ does not exist due to both parts being neutral.