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Q. The total number of orbitals in the principal shell of $He ^{+}$ that has energy equal to $\frac{- Rhc }{4}$ (where $R$ is Rydberg's constant)

Structure of Atom

Solution:

T.E. $=-Rhc \times \frac{z^{2}}{n^{2}}$

$\frac{- Rhc }{4}=- Rhc \times \frac{4}{ n ^{2}}$

$n^{2}=16$

$ \Rightarrow n=4$