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  4. The total number of moles of neutrons present in 108 mL H 2 O (l) are

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Q. The total number of moles of neutrons present in $108 mL H _{2} O (l)$ are

NTA AbhyasNTA Abhyas 2020Some Basic Concepts of Chemistry

Solution:

$\therefore $ density of $H _{2} O (1)=1 g / mL$

$1 mL$ contains $=1 gH _{2} O$

$108 mL$ contains $=108 gH _{2} O$

Number of moles of $H _{2} O (l)=\frac{108}{18}=6$

$H$ has no neutron, Number of neutrons in $O =16-8=8$

Number of moles of neutrons in 1 mole of $H _{2} O =0+8=8$

Number of moles of neutrons in 6 mole of $H _{2} O =6 \times 8=48$