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  4. The total number of atoms of all elements present in 1 mole of ammonium dichromate is

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Q. The total number of atoms of all elements present in $ 1 $ mole of ammonium dichromate is

AMUAMU 2010Some Basic Concepts of Chemistry

Solution:

In in $1$ mole of $(NH_{4})_{2} Cr_{2}O_{7}$, the number of molecules $=6.023\times 10^{23}$
$\therefore $ In $1$ mole $(NH_{4})_{2} Cr_{2}O_{7}$, the total number of atoms of all elements present
$=6.023\times 10^{23}\times19$
$=114.43\times 10^{23}$