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Q. The total number of $7$ digit positive integral numbers with district digits that can be formed using the digits $4, 3, 7, 2, 1, 0, 5$ is

KEAMKEAM 2016Permutations and Combinations

Solution:

Given, digits are 4, 3, $7,2,1,0,5$.
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Total ways $=6 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 $
$=6 \times 6 !=6 \times 720=4320$