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Q. The total flux associated with given cube will be ,where $'a'$ Is side of cube:
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
Flux linked with cube due to one charge is
$\phi=\frac{q}{8 \epsilon _{0}}$
Flux Due to all charges will be
$\phi=\frac{\left(2 + 1 + 4 + 3 + 6 + 5 + 8 + 7\right) \times \left(10\right)^{- 6}}{8 \left(\epsilon \right)_{0}}\phi=\frac{36 \times \left(10\right)^{- 6}}{8 \times 8 . 85 \times \left(10\right)^{- 12}}=508\times \left(10\right)^{3}N\,m^{2}C^{- 1}$