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Q. The total energy of an electron in $4^{th}$ orbit of hydrogen atom is

J & K CETJ & K CET 2014Atoms

Solution:

For hydrogen atom
$ E_{n}=\frac{-13.6}{n^{2}} \,eV $
$ {E_n}=\frac{-13.6}{4^{2}} \,eV $
$ =-0.85\,eV $