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Q. The total electrical resistance between the points A and B of the circuit shown isPhysics Question Image

BVP MedicalBVP Medical 2013

Solution:

$ {{R}_{1}}=10+10+10=30\Omega $ $ {{R}_{3}}=20+20=40\Omega $ $ \frac{1}{{{R}_{eq}}}=\frac{1}{30}+\frac{1}{20}+\frac{1}{40}=\frac{4+6+3}{120}=\frac{13}{120} $ $ {{R}_{eq}}=\frac{120}{13}=9.23\Omega $