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Q. The total cost of a score of apples and a dozen of oranges is greater than or equal to $₹ 420$. The cost of each apple cannot exceed $₹ 15$. Find the minimum possible cost of each orange (in ₹) $(1$ score $=20)$.

Linear Equations

Solution:

Let the cost of each apple $=₹ x$
Cost of each orange $=₹ \gamma$
$20 x+12 y \geq 420$
$(\because 1 \text { score }=20)$
To get the minimum cost of orange, the apple cost must be maximum, i.e., ₹ 15 .
$\therefore 20 \times 15+12 y \geq 420 $
$12 y \geq 420-300$
$\Rightarrow 12 \gamma \geq 120$
$y \geq 10$
The minimum possible value is 10 .