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Q. The total area of cross-section is $0.25m^{2}$ . If the blood is flowing at the rate of $100cm^{3}/sec$ , then the average velocity of flow of blood through the capillaries is :

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Solution:

Rate of flow $Q=Av$
$v=\frac{Q}{A}=\frac{100 \times 10^{- 6}}{0 . 25}=4\times 10^{- 4}m/s=0.4mm/s$