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Q.
The time taken by an alternating current of $ 50\,Hz $ in reaching from zero to its maximum value will be
J & K CETJ & K CET 2005Alternating Current
Solution:
An alternating current is one whose magnitude changes continuously with time between zero and a maximum value and whose direction reverses periodically. The relation between frequency $(f)$ and time $(T)$ is
$T = \frac{ 1}{ f } = \frac{ 1}{ 50} = 0.02\, s $
As is clear from the figure time taken to reach the maximum value is
$ \frac{ T}{ 4 } = \frac{ 0.02 }{ 4} = 0.005 \,s $