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  3. Chemistry
  4. The time required to coat a metal surface of 80 cm 2 with 5 × 10-3 cm thick layer of silver (density .1.05 g cm -3) with a passage of 3 A current through a silver nitrate solution is

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Q. The time required to coat a metal surface of $80 \,cm ^{2}$ with $5 \times 10^{-3} cm$ thick layer of silver (density $\left.1.05\, g \,cm ^{-3}\right)$ with a passage of $3 \,A$ current through a silver nitrate solution is

Electrochemistry

Solution:

Weight of Ag required $=80 \times 5 \times 10^{-3} \times 1.05$

$=0.42 \,g \,\,\,\,\,\, ( wt. =V \times d)$

$\because w=\frac{E I t}{96500} \,\,\,\, \therefore \,\,\,\, 0.42=\frac{108 \times 3 \times t}{96500} ; t=125\, s$