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Q. The time period of a satellite of earth is $24$ hours. If the separation between the earth and the satellite is decreased to one fourth of the previous value, then its new time period will become.

JEE MainJEE Main 2023Gravitation

Solution:

$ T ^2 \propto R ^3$
$ \frac{ T _1^2}{ T _2^2}=\frac{ R _1^3}{ R _2^3} \Rightarrow\left(\frac{ T _1}{ T _2}\right)^2=\left(\frac{ R }{\frac{ R }{4}}\right)^3$
$\therefore \frac{ T _1^2}{ T _2^2}=64 $
$\therefore T _2^2=\frac{ T _1^2}{64}$
$\therefore T _2=\frac{24}{8}=3$