Tardigrade
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Chemistry
The time of decay for a chemical reaction is given by t = 4tl/2. The relation between the mean life (T) and time of decay (t) is given by
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Q. The time of decay for a chemical reaction is given by $t = 4t_{l/2.} $ The relation between the mean life $(T)$ and time of decay (t) is given by
Chemical Kinetics
A
$ t = 2T\,ln\,2 $
B
$ t = 4T\,ln\,2$
C
$t = 2T^4 ln2$
D
$t = \frac{I}{T^2} ln2 $
Solution:
$t_{1 / 2}=\frac{t}{4}$ and $t_{1 / 2}=T \ln 2$
So, $\frac{t}{4}=T \ln 2 ; t=4 T \ln 2$