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Q. The threshold of hearing for the human ear is $10^{-12}\, W \,m ^{-2} .$ This is taken as the standard level. The intensity of sound is $1 \,W \,m ^{-2}$. Expressed in decibel, it has intensity

Waves

Solution:

Here, Decibel level $=10 \log _{10}\left(\frac{1\, Wm ^{-2}}{10^{-12}\, Wm ^{-2}}\right)$
$=10 \log _{10} 10^{12}=12 \times 10 \,db =120\, db$