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  4. The threshold energy is given as E0 and radiation of energy E falls on metal, then K.E. is given as

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Q. The threshold energy is given as $E_{0}$ and radiation of energy $E$ falls on metal, then K.E. is given as

Structure of Atom

Solution:

$E =$ Incident energy
$E _{0}=$ Threshold energy
$E= E _{0}+ K . E$
$K.E.= E - E _{0}$

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