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Chemistry
The third line of the Balmer series in the emission spectrum of the hydrogen atom is due to the transition from the
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Q. The third line of the Balmer series in the emission spectrum of the hydrogen atom is due to the transition from the
Structure of Atom
A
fourth Bohr orbit to the first Bohr orbit
14%
B
fifth Bohr orbit to the second Bohr orbit
77%
C
sixth Bohr orbit to the third Bohr orbit
7%
D
seventh Bohr orbit to the third Bohr orbit
2%
Solution:
In Balmer series, $n_1=2$ and $n_2 = 3$, $4$, $5$ So, third line arises by the emission of $5^{th}$ orbit to $2^{nd}$ orbit.