Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The third line of the Balmer series in the emission spectrum of the hydrogen atom is due to the transition from the

Structure of Atom

Solution:

In Balmer series, $n_1=2$ and $n_2 = 3$, $4$, $5$ So, third line arises by the emission of $5^{th}$ orbit to $2^{nd}$ orbit.