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Q. The third ionization enthalpy is minimum for :

JEE MainJEE Main 2020The d-and f-Block Elements

Solution:

Electronic configuration of
$\begin{matrix}_{25}Mn&_{26}Fe&_{27}CO&_{28}Ni\\ M=\left[Ar\right]3d^{5}\,4s^{2}&\left[Ar\right]3d^{6}\,4s^{2}&\left[Ar\right]3d^{7}\,4s^{2}&\left[Ar\right]3d^{8}\,4s^{2}\\ M^{2+}=\left[Ar\right]3d^{5}\,4s^{0}&\left[Ar\right]3d^{6}\,4s^{0}&\left[Ar\right]3d^{7}\,4s^{0}&\left[Ar\right]3d^{8}\,4s^{0}\end{matrix}$
So third ionisation energy is minimum for Fe.