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Physics
The thermal capacity of 100 g of aluminum (specific heat =0.2 cal / g ° C ) is
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Q. The thermal capacity of $100 \,g$ of aluminum (specific heat $=0.2 \,cal / g ^{\circ} C$ ) is
Thermal Properties of Matter
A
$0.002 \,cal /{ }^{\circ} C$
B
$20 \, cal /{ }^{\circ} C$
C
$200 \,cal /{ }^{\circ} C$
D
$100 \, cal /{ }^{\circ} C$
Solution:
Thermal capacity $= m . C$
$=100 \times 0.2=20 \,cal /{ }^{\circ} C$