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Q.
The term independent of $x$ in the expansion of $\left(x-\frac{1}{x}\right)^4\left(x+\frac{1}{x}\right)^3$ is:
Binomial Theorem
Solution:
$\left(x-\frac{1}{x}\right)\left(x^2-\frac{1}{x^2}\right)^3=\left(x-\frac{1}{x}\right)\left({ }^3 C_0 x^6-{ }^3 C_1 x^2+{ }^3 C_2 x^{-2}-{ }^3 C_3 x^{-6}\right)$
There is no term independent of $x$