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  4. The term containing x in the expansion of (x2+(1/x))5 is -

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Q. The term containing $x$ in the expansion of $\left(x^2+\frac{1}{x}\right)^5$ is -

Binomial Theorem

Solution:

Let its come in $T_{r+1}$
then $T_{r+1}={ }^5 C_r\left(x^2\right)^{5-r} \cdot x^{-r}$
$\Rightarrow 10-3 r=1 $
$ 3 r=9$
$ r=3$
Hence $T _{3+1}= T _4$