As we know the last two digits of $10 !$ and above factorials will be zero- zero.
$\therefore 1 !+4 !+7 !+10 !+12 !+13 !+15 !+16 !+17 !$
$=1+24+5040+10 !+12 !+13 !+15 !+16 !+17 !$
$=5065+10 !+12 !+13 !+15 !+16 !+17 !$
In this series, the digit in the ten place is $6$ which is divisible by $3 !$