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Q.
The temperature on a Fahrenheit scale is $98.6^{\circ} F ?$ What is the corresponding temperature on a kelvin scale?
AMUAMU 2014
Solution:
We know that, $t_{F}=32^{o}+\frac{9}{5} t_{c}$
$\left[t_{f}=98.6^{\circ} F(\right.$ given $\left.)\right]$
$98.6=32=\frac{9}{5} t_{c}$
$493=160+9 t_{c}$
$9 t_{c}=493-160$
$t_{c}=\frac{333}{9}$
$t_{c}=37^{\circ} C$
So, the temperature on a Kelvin scale is
$=37+273=310 \,K$
or $\approx 310.2 \,K$