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  4. The temperature of source and sink of a heat engine are 127° C and 27° C respectively. An inventor claims its efficiency to be 26 %, then:

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Q. The temperature of source and sink of a heat engine are $127^{\circ} C$ and $27^{\circ} C$ respectively. An inventor claims its efficiency to be $26 \%$, then:

Thermodynamics

Solution:

$\eta=1-\frac{300}{400}=\frac{100}{400}=\frac{1}{4}$
$\eta=\frac{1}{4} \times 100=25 \%$
Hence, it is not possible to have efficiency more than $25 \%$.