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Q. The temperature of an open room of volume $30 \, m^3$ increases from $17^{\circ}C$ to $27^{\circ}C$ due to the sunshine. The atmospheric pressure in the room remains $1 \times 10^5 \, Pa$. If $n_i$ and $n_f$ are the number of molecules in the room before and after heating, then $n_f-n_i$ will be :

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Solution:

$n_1$ = initial number of moles
$n_{1} = \frac{P_{1}V_{1}}{RT_{1}} = \frac{10^{5} \times30}{8.3 \times290}$
$\approx 1.24 \times10^{3} $
$n_2$ = final number of moles
$=\frac{P_{2}V_{2}}{RT_{2}} = \frac{10^{5} \times30}{8.3 \times300}$
$\approx 1.20 \times10^{3}$
Change of number of molecules :
$n_{f} - n_{i} = \left(n_{2} - n_{1}\right)\times6.023 \times10^{23}$
$\approx - 2.5 \times10^{25} $